X

Number of individuals

Using example data:

ID	phenocode	age
FG1	EXAMPLE_ENDPOINT	45
FG1	ENDPOINT_XYZ	46
FG1	DEATH	47
FG2	EXAMPLE_ENDPOINT	30
FG2	EXAMPLE_ENDPOINT	30.1
FG3	ENDPOINT_XYZ	50

In this example the number of individuals is 2, since only 2 unique individuals (FG1 and FG2) have EXAMPLE_ENDPOINT events.

X

Unadjusted prevalence

Using example data:

ID	phenocode	age
FG1	EXAMPLE_ENDPOINT	45
FG1	ENDPOINT_XYZ	46
FG1	DEATH	47
FG2	EXAMPLE_ENDPOINT	30
FG2	EXAMPLE_ENDPOINT	30.1
FG3	ENDPOINT_XYZ	50

In this example the unadjusted prevalence is 66 %.

The unadjusted prevalence is the number of individuals having an endpoint divided by the total number of individuals.

Here:

• 2 unique individuals (FG1 and FG2) have EXAMPLE_ENDPOINT events
• 1 individual (FG3) has no EXAMPLE_ENDPOINT event

So the unadjusted prevalence is 2 / 3 = 66 %.

X

Mean age at first event

Using example data:

ID	phenocode	age
FG1	EXAMPLE_ENDPOINT	45
FG1	ENDPOINT_XYZ	46
FG1	DEATH	47
FG2	EXAMPLE_ENDPOINT	30
FG2	EXAMPLE_ENDPOINT	30.1
FG3	ENDPOINT_XYZ	50

In this example the mean age at first event is 37.5.

The mean age at first event for EXAMPLE_ENDPOINT is computed by:

• selecting individuals having EXAMPLE_ENDPOINT: FG1 and FG2
• for these individuals, taking the age of their first event of EXAMPLE_ENDPOINT: 45 for FG1 and 30 for FG2
• computing the mean of these values

So the mean age at first event is Mean(45, 30) = 37.5.